Part Number:LM2665
I have a 5V rail and want to charge a 2.7V supercapacitor. It looks reasonable to use the LM2665 to generate 2.5V (Vin/2) and use that to charge the capacitor. My question is whether I can rely on the 40mA max current of the LM2665 to operate as constant-current charger, or whether that will potentially harm the device. The discharged supercap will basically look like a short circuit so I worry that this won't work. I could put a 62Ω resistor in series with the supercap, thus limiting the max current to 40mA, but as the capacitor voltage rises the charging current will decrease, significantly stretching out charging time.
Any advice on this, either for a way to use the LM2665 or some other circuit I am overlooking, is appreciated!
