bq34Z100 with Lead Acid chemistry battery

Hi,

I use an Lead Acid battery 6S - 12Volt and I don't understand how to calculate Flash Update OK Cell Volt.

In bq34z100 data sheet I find in paragraph 9.2.2.1.3 this formula : Flash Update OK Cell Volt = 2800 mV × Number Of Series Cells × 5000/Voltage Divider

So, for my application =>  Flash Update OK Cell Volt = 2800 mV ×6 × 5000/19299 = 4353 mV !!

I think that isn't the right value because this is a formula for Lithium chemistry!

Do you have the good formula for LEAD chemistry?

Thanks

Loïc